fold: require --from flag for folding revisions to working copy
It's very easy to think that "hg fold 4::6" will fold exactly those
revisions. In reality, it will fold those *and* any revisions between
them and the working copy. To prevent users from making that mistake,
require the use of a new --from flag for folding revisions from the
given set to the working copy. With this change, I'm sure some users
will be surprised that the command can not be run without either
--from or --exact, but at least the consequences will be smaller (the
command simply aborts and the user can try again).
#!/usr/bin/env python
import os, os.path as op, re, sys
# line starts with two chars one of which is not a space (and both are not
# newlines obviously) and ends with one or more newlines followed by two spaces
# on a next line (indented text)
CODEBLOCK = re.compile(r'()\n(([^ \n][^\n]|[^\n][^ \n])[^\n]*)\n+ ')
INDEX = '''
Mercurial tests
===============
.. toctree::
:maxdepth: 1
'''
def rstify(orig, name):
header = '%s\n%s\n\n' % (name, '=' * len(name))
content = header + orig
content = CODEBLOCK.sub(r'\n\1\n\n::\n\n ', content)
return content
def main(base):
if os.path.isdir(base):
one_dir(base)
else:
one_file(base)
def one_dir(base):
index = INDEX
#doc = lambda x: op.join(op.dirname(__file__), 'docs', x)
for fn in sorted(os.listdir(base)):
if not fn.endswith('.t'):
continue
name = os.path.splitext(fn)[0]
content = one_file(op.join(base, fn))
target = op.join(base, name + '.rst')
#with file(doc(name + '.rst'), 'w') as f:
with file(target, 'w') as f:
f.write(content)
index += '\n ' + name
#with file(doc('index.rst'), 'w') as f:
# f.write(index)
def one_file(path):
name = os.path.basename(path)[:-2]
return rstify(file(path).read(), name)
if __name__ == '__main__':
if len(sys.argv) != 2:
print 'Please supply a path to tests dir as parameter'
sys.exit()
main(sys.argv[1])